[LINUX] Get the output value of the command (as received by xargs)

Hello. I got the output value of the command ($ (command)` ``), while receiving it with xargs. I received a comment and corrected it so that it works correctly. In this example, we are checking the output value of the `` `basename command.

$ find . -name "*.txt" | xargs -I% sh -c 'echo "$(basename "%" .txt)"'
$ ls .
a.txt  b.txt

While read loop use

while readI also tried using a loop.

$ find . -name "*.txt" | while read f; do echo "$(basename "$f" .txt)"; done

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