[PYTHON] AOJ Einführung in die Programmierung Thema Nr. 5, Thema Nr. 6

Thema Nr. 5

ITP1_5_A

Zeichne ein Rechteck

Python

def Square(H, W):
    for i in range(0, H):
        for j in range(0, W):
            print("#", end='')
            
        print('')

while True:
    H, W = list(map(int, input().split()))
    
    if H == 0 and W == 0:
        break
    else:
        Square(H, W)
        print('')

ITP1_5_B

Einen Rahmen zeichnen

Python

def Square(H, W):
    for i in range(0, H):
        for j in range(0, W):
            if i==0 or i==H-1 or j==0 or j==W-1:
                print("#", end='')
            else:
                print(".", end='')
            
        print('')

while True:
    H, W = list(map(int, input().split()))
    
    if H == 0 and W == 0:
        break
    else:
        Square(H, W)
        print('')

ITP1_5_C

Ein Schachbrett zeichnen

Python

def Square(H, W):
    for i in range(0, H):
        for j in range(0, W):
            if (i+j)%2==0:
                print("#", end='')
            else:
                print(".", end='')

        print('')

while True:
    H, W = list(map(int, input().split()))
    
    if H == 0 and W == 0:
        break
    else:
        Square(H, W)
        print('')

ITP1_5_D

Strukturierte Programmierung

Python

n = int(input())

for i in range(1, n+1):
    x = i
    if x%3==0:
        print(f" {i}", end='')
    else:
        while x>0:
            if x%10==3:
                print(f" {i}", end='')
                break
            else:
                x = x // 10
print('')

Thema # 6

ITP1_6_A

Inversion der Zahlenfolge

Python

n = int(input())
A = list(map(int, input().split()))

for i in reversed(range(0, n)):
    if i==0:
        print(f"{A[i]}")
    else:
        print(f"{A[i]} ", end='')

ITP1_6_B

Die fehlende Karte finden

Python

card = [[False for i in range(13)] for j in range(4)]
pattern = ['S', 'H', 'C', 'D']

n = int(input())
for i in range(0, n):
    m, h = list(map(str, input().split()))
    card[pattern.index(m)][int(h)-1] = True

for i in range(0, 4):   
    for j in range(0, 13):
        if card[i][j]==False:
            print(f"{pattern[i]} {j+1}")

ITP1_6_C

Anzahl der Bewohner des öffentlichen Gebäudes

Python

card = [[False for i in range(13)] for j in range(4)]
pattern = ['S', 'H', 'C', 'D']

floor = [[[0 for i in range(10)] for j in range(3)] for k in range(4)]

n = int(input())
for i in range(0, n):
    b, f, r, v = list(map(int, input().split()))
    floor[b-1][f-1][r-1] += v
    
for b in range(0, 4):
    for f in range(0, 3):
        for r in range(0, 10):
            if r==9:
                print(f" {floor[b][f][r]}")
            else:
                print(f" {floor[b][f][r]}", end='')
    if b<3:
        print(f"####################")

ITP1_6_D

Produkt aus Vektor und Matrix

Python

n, m = list(map(int, input().split()))

A = [[0 for i in range(m)] for j in range(n)]
B = [0 for i in range(m)]

for i in range(0, n):
    a = list(map(int, input().split()))
    
    for j in range(m):
        A[i][j] = a[j]

for i in range(0, m):
    b = int(input())
    B[i] = b
    
for i in range(0, n):
    ans = 0
    for j in range(0, m):
        ans += A[i][j] * B[j]
    print(ans)