[PYTHON] Get the IPv4 address assigned to the network interface in code (Linux)

However, the output of the ʻifconfig command and the ʻip command should not be parsed.

On Linux, you can get it with ʻioctl (SIOCGIFADDR) `.

It is almost the same as the script of the source (Reference 1 below). With Python, it's easy because you can write so far with the distribution attached.

import sys, socket, struct
from fcntl import ioctl

SIOCGIFADDR = 0x8915

if len(sys.argv) < 2:
  print >> sys.stderr, "Usage:", sys.argv[0], "<interface name>"
  sys.exit()

interface = sys.argv[1]

s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
try:
  ifreq  = struct.pack('16s16x', interface)
  ifaddr = ioctl(s.fileno(), SIOCGIFADDR, ifreq)
finally:
  s.close()

_, sa_family, port, in_addr = struct.unpack('16sHH4s8x', ifaddr)
print socket.inet_ntoa(in_addr)

Reference

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