[PYTHON] Configure a module with multiple files in Django

I wonder if the terms in the title are correct. .. .. .. .. ..

A memorandum for myself

Purpose

When creating a program that uses Django To be convenient when the scale of the application grows Organize the procedure for splitting modules such as views and models into multiple files.

Premise

The environment is as follows

Ubuntu 16.04
python 3.5.2
django 1.10.5

procedure

Here, let's divide models.py into multiple files.

Split model into multiple files

initial state

__init__.py
admin.py
apps.py
migrations
models.py
tests.py
views.py

Here, modify models.py so that 1 file = 1 model class.

With the models directory__init__.Prepare py file

__init__.py
admin.py
apps.py
migrations
models
    __init__.py
    task.py
tests.py
views.py

Delete models.py and prepare the models directory as shown in the code above. A file that describes the init.py__ file and the model class in it. Create (here, task.py).

task.py

from django.db import models


class Task(models.Model):
    """
    Task to do.
    """
    name = models.CharField(max_length=30)
    startTime = models.DateTimeField()
    endTime = models.DateTimeField()
    memo = models.CharField(max。_length=200)

__init__py file

from webui.models.task import Task #Import the class created above

Split view into multiple files

The file division method is the same.

1. Delete views.py
2. Create a views directory
3. Create an appropriate file under the views directory
4. Create views / ＿＿init ＿＿.py file
5. Import the classes and methods in the file created in 3. with the __init __.py file

File split

__init__.py
admin.py
apps.py
migrations
models
    __init__.py
    task.py
tests.py
views
    __init__.py
    task_view.py

Description in urls.py

The view module needs to be described in urls.py

If you are defining a view on a method basis

Split views into multiple files If you are doing like

urls.py(Method based)

urlpatterns = [
    ...,
    url(r'^Appropriate regular expression',Application name.views.file name.Method name)
]

The method to specify from ... import is also in the link mentioned at the beginning of this section. Although it is described, the same method name cannot be specified, so the above code example I think it's better to use ** maybe **.

If you are defining a view on a class basis

In the case of a class unit, as shown in Make Django views.py a class It becomes as follows.

urls.py(Class based)

urlpatterns = [
    ...
    url(r'^/URL regular expression/$',Application name.views.view class name.as_view()),
    ...
]

By declaring from ... import as well as method-based You shouldn't need to write the package name.

Reference material

Make Django views.py a class Split views into multiple files