[Blender x Python] Let's arrange a lot of Susanne neatly !!
table of contents
- Make one Sae Yamamoto appear
- Arrange Susanne in a row
- Arrange Susanne in two dimensions
- Arrange Susanne in three dimensions
- Sample code
0. Make one Sae Yamamoto appear
This is the code to make one of Sae Yamamoto introduced in the previous article appear. This time we will apply this.
import bpy
bpy.ops.mesh.primitive_monkey_add(
size=2,
enter_editmode=False,
align='WORLD',
location=(0, 0, 0),
scale=(1, 1, 1)
)
It may seem long at first glance, but it was a story that you can think simply by ** abstracting, compressing and symbolizing information ** (↓)
===>primitive_monkey_add(□,□,□,□,□)
Code meaning: Sae Yamamoto appears. At that time, you can change the position and size.
- By the way, import is for using a library (a collection of useful code created by someone).
1. Arrange Susanne in a row
Iterates using a mechanism called ◯ ** for loop **. The key to understanding iterative processing is
** Number of processes ** When ** Numerical value that changes with processing **
** Think separately **.
I'm not sure right now, but it's okay !!
1-0.x Coordinates are staggered by 1
◯ The point is that the numerical value that changes with processing increases by one.
import bpy
#i is 0 → 1 → 2 → 3 → 4
for i in range(0,5):
bpy.ops.mesh.primitive_monkey_add(
size=2,
enter_editmode=False,
align='WORLD',
#Attention ↓
location=(i, 0, 0),
scale=(1, 1, 1)
)
When the above code is symbolized (abstracted),
i → 0,1,2,3,4 : ===>primitive_monkey_add(□,□,□,□,□)
Call like.
Meaning: Each time i repeats the process, it increases by ** 1. If i satisfies ** 0 <= i <5 **, the process of making Sae Yamamoto appear is performed. Then, substitute the value of i into the value of the x coordinate.
The number of processing is 5 times The numerical value that changes with processing is 0 → 1 → 2 → 3 → 4.
When you do this, it will look like the picture below. Somehow cute .. ??
◯ Point: ** range (from where to where) ** It is used to determine the range of iteration.
1-1.x Coordinates are shifted by 3 (Part 1)
◯ Point is the part where the x coordinate of Sae Yamamoto is written as ** i * 3 **. The * symbol is a multiplication symbol.
import bpy
#i is 0 → 1 → 2 → 3 → 4
for i in range(0,5):
bpy.ops.mesh.primitive_monkey_add(
size=2,
enter_editmode=False,
align='WORLD',
#Attention ↓
location=(i * 3, 0, 0),
scale=(1, 1, 1)
)
The x coordinate of Sae Yamamoto is i * 3. In other words First time of processing (i = 0) → ** i * 3 = 0 ** Second time of processing (i = 1) → ** i * 3 = 3 ** Third time of processing (i = 2) → ** i * 3 = 6 ** 4th processing (i = 3) → ** i * 3 = 9 ** 5th process (i = 4) → ** i * 3 = 12 **
1-2. Place the x coordinates by 3 (Part 2)
◯ The point is in range ().
import bpy
#i is 0 → 3 → 6 → 9 → 12
for i in range(0,13,3):
bpy.ops.mesh.primitive_monkey_add(
size=2,
enter_editmode=False,
align='WORLD',
#Attention ↓
location=(i, 0, 0),
scale=(1, 1, 1)
)
range () can be range (first value, last value, step)
You can decide how many numbers you want to skip ** in the range from the first number to the last number.
In other words, for i in range (0,13,3): means that every three numbers from 0 are selected and assigned to i, which is repeated within the range of i <13.
⬇️
0 1 2 3 4 5 6 7 8 9 10 11 12
First time of processing → ** i = 0 ** Second time of processing → ** i = 3 ** Third time of processing → ** i = 6 ** 4th processing → ** i = 9 ** 5th process → ** i = 12 **
- Range (0,5) is actually range (0,5,1), and you can think that 1 is omitted.
2. Arrange Susanne in two dimensions
◯ The point is that ** another for loop is inside the for loop **.
import bpy
#i is 0 → 3 → 6 → 9 → 12
for i in range(0,13,3):
for j in range(0,13,3):
bpy.ops.mesh.primitive_monkey_add(
size=2,
enter_editmode=False,
align='WORLD',
#Attention ↓
location=(i, j, 0),
scale=(1, 1, 1)
)
- The symbol **: ** indicates that the conditional statement ends here.
When symbolized (abstracted),
i = 0→3→6→9→12:
j = 0→3→6→9→12:
===>primitive_monkey_add(□,□,□,□,□)
Call like.
this is,
( i , j ) = (0,0),(0,3),(0,6),(0,9),(0,12),
(3,0),(3,3),(3,6),(3,9),(3,12),
(6,0),(6,3),(6,6),(9,9),(12,12),
(9,0),(9,3),(9,6),(9,9),(9,12),
(12,0),(12,3),(12,6),(12,9),(12,12)
about it.
3. Arrange Susanne in three dimensions
◯ It is the application mentioned earlier.
import bpy
for i in range(0,13,3):
for j in range(0,13,3):
for k in range(0,13,3):
bpy.ops.mesh.primitive_monkey_add(
size=2,
enter_editmode=False,
align='WORLD',
#Attention ↓
location=(i, j, k),
scale=(1, 1, 1)
)
4. Sample code
◯ Only the sample code is summarized.
4-0. Code that makes only one Sae Yamamoto appear
import bpy
bpy.ops.mesh.primitive_monkey_add(
size=2,
enter_editmode=False,
align='WORLD',
location=(0, 0, 0),
scale=(1, 1, 1)
)
4-1. Code to arrange Sae Yamamoto in a row (shift by 1)
import bpy
#i is 0 → 1 → 2 → 3 → 4
for i in range(0,5):
bpy.ops.mesh.primitive_monkey_add(
size=2,
enter_editmode=False,
align='WORLD',
#Attention ↓
location=(i, 0, 0),
scale=(1, 1, 1)
)
4-2. Code for arranging Sae Yamamoto in a row (shift by 3: Part 1)
import bpy
#i is 0 → 1 → 2 → 3 → 4
for i in range(0,5):
bpy.ops.mesh.primitive_monkey_add(
size=2,
enter_editmode=False,
align='WORLD',
#Attention ↓
location=(i * 3, 0, 0),
scale=(1, 1, 1)
)
4-3. Code for arranging Sae Yamamoto in a row (shift by 3: Part 2)
import bpy
#i is 0 → 3 → 6 → 9 → 12
for i in range(0,13,3):
bpy.ops.mesh.primitive_monkey_add(
size=2,
enter_editmode=False,
align='WORLD',
#Attention ↓
location=(i, 0, 0),
scale=(1, 1, 1)
)
4-4. Code for arranging Susanne in two dimensions
import bpy
#i is 0 → 3 → 6 → 9 → 12
for i in range(0,13,3):
for j in range(0,13,3):
bpy.ops.mesh.primitive_monkey_add(
size=2,
enter_editmode=False,
align='WORLD',
#Attention ↓
location=(i, j, 0),
scale=(1, 1, 1)
)
4-5. Code for arranging Susanne in three dimensions
import bpy
for i in range(0,13,3):
for j in range(0,13,3):
for k in range(0,13,3):
bpy.ops.mesh.primitive_monkey_add(
size=2,
enter_editmode=False,
align='WORLD',
#Attention ↓
location=(i, j, k),
scale=(1, 1, 1)
)
4-6. Codes arranged in a circle
import bpy
import math
#Assign a number to a variable
#To make it easy to change the numbers
n = 12
r = 10.0
for i in range(0, n):
rad = 2 * math.pi * i /n #Angle calculation 2π i/n
x = r * math.cos(rad) #x coordinate calculation radius*cosθ
y = r * math.sin(rad) #y coordinate calculation radius*sinθ
bpy.ops.mesh.primitive_monkey_add(
size=2,
enter_editmode=False,
align='WORLD',
#Attention ↓
location=(x, y, 0),
scale=(1, 1, 1)
)
4-7. Cords arranged in a spiral
import bpy
import math
n = 144
r = 10.0
for i in range(0, n):
rad = 2 * math.pi * i /24 #Angle calculation 2π i/24
x = (r * i)/10 * math.cos(rad) #x coordinate calculation radius*cosθ
y = (r * i)/10 * math.sin(rad) #y coordinate calculation radius*sinθ
bpy.ops.mesh.primitive_monkey_add(
size=2,
enter_editmode=False,
align='WORLD',
#Attention ↓
location=(x, y, 0),
scale=(1, 1, 1)
)
4-8. Code to make a spiral
import bpy
import math
n = 144
r = 10.0
for i in range(0, n):
rad = 2 * math.pi * i /12 #Angle calculation 2π i/12
x = r * math.cos(rad) #x coordinate calculation radius*cosθ
y = r * math.sin(rad) #y coordinate calculation radius*sinθ
bpy.ops.mesh.primitive_monkey_add(
size=2,
enter_editmode=False,
align='WORLD',
#Attention ↓
location=(x, y, i),
scale=(1, 1, 1)
)
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