Zundokokiyoshi with python / ruby / Lua

Original story ――Honestly, it's amazing to come up with this. ――It's a little more complicated than fizzbuzz, so I think it's good for studying languages.

python version

Final code

――I made a mistake in the basics, so I was pointed out. ――We also received some refactoring.

** Dung four times **

def kiyoshi():
    zd=deque(list(),5)
    while ''.join(zd)!='Zunzunzundoko':
        word=choice(['Dung','Doco'])
        print(word)
        zd.append(word)
    print('Ki yo shi!')

Wrong code below

Like this? deque It's pretty simple to use.

from collections import deque
from random import choice
def kiyoshi():
    zd=deque(list(),4)
    while True:
        if "".join(zd)=='Zunzunzundoko':
            print("Ki yo shi!")
            break
        else:
            word=choice(['Dung','Doco'])
            print(word)
            zd.append(word)

monitoring

%matplotlib inline
import pandas as pd
def kiyoshi2():
    c=0
    zd=deque(list(),4)
    while True:
        if "".join(zd)=='Zunzunzundoko':
            print("Ki yo shi!")
            break
        else:
            word=choice(['Dung','Doco'])
            print(word)
            zd.append(word)
            c+=1
    return c
rslts=[kiyoshi2() for i in range(10000)]
pd.DataFrame(rslts).hist(bins=30)

The original algorithm seems to use zun counter.

def kiyoshi_org():
    zun=0
    while True:
        word=choice(['Dung','Doco'])
        print (word)
        if word == 'Dung':
            zun+=1
        elif zun>=3:
            print("Ki yo shi!")
            break
        else: zun=0

ruby version

-Here is smarter. ――Ruby is fun.

kiyoshi.rb

#! ruby -Ku
require "kconv"

def kiyoshi()
  zd=[]
  while zd.join!="Zunzunzundoko" do
    word=["Dung","Doco"].sample
    p word
    zd<<word
    zd.slice!(0) if zd.length>=6
  end
  p "Ki yo shi!"
end

def kiyoshi_org()
  zun=0
  while true do
    word = ["Dung","Doco"].sample
    p word
    if word == "Dung"
      zun+=1
    elsif zun <= 3
      zun = 0
    else
      p "Ki yo shi!"
      break
    end
  end
end

kiyoshi()
kiyoshi_org()

I'm not used to the do end syntax.

Lua version

--I wrote lua for the first time. I think it's early. ――I searched for an array concatenation, but couldn't find it. ――Japanese characters are garbled, so for the time being, use Roman characters.

kiyoshi.lua

function kiyoshi_org()
  words={"zun","doko"}
  zun=0
  while true do
    word = words[math.random (#words)]
    print (word)
    if word == "zun" then zun = zun + 1
    elseif zun < 4 then zun =0
    else break
    end
  end
  print "ki yo shi!"
end


function kiyoshi()
  words={"zun","doko"}
  zd={}
  while true do
    word = words[math.random (#words)]
    print (word)
    table.insert(zd, word)
    str=""
    for i,value in ipairs(zd) do
      str = str .. value
    end
    if #zd==5 then
      if str == "zunzunzunzundoko" then break
      else table.remove(zd,1)
      end
    end
  end
  print "ki yo shi!"
end

What should I do next ...