problem | https://paiza.jp/poh/ec-campaign |
---|---|
Time list/C++ | http://qiita.com/cielavenir/items/a61cfe8390eb16866ae5 |
Python/Ruby(1) | http://qiita.com/cielavenir/items/b10ff4d201150f525062 |
C#/Java/Python/Ruby | http://qiita.com/cielavenir/items/d89e85f069cf570e6786 |
Perl/PHP | http://qiita.com/cielavenir/items/1a650a4c41d7bdd31392 |
JavaScript | http://qiita.com/cielavenir/items/a85b985888fdc15c52b7 |
Go/CoffeeScript/Scala/R/Bash | http://qiita.com/cielavenir/items/79016a0afd30470f440d |
VB/F#/D | http://qiita.com/cielavenir/items/cb6094bab56253de992c |
Implemented reading input at once with Python / Ruby. Also, I found that C # and Java have a 2-minute search library as standard, so I ported it.
Works with Python * 3.3
paizapoh1_read.py
#!/usr/bin/python
import sys,io,bisect
def init():
reader = io.open(sys.stdin.fileno(),'rb',0)
if sys.version_info[0]<3:
s=reader.readall()
if sys.version_info[0]>=3:
s=str(reader.readall(),encoding='utf8')
raw_input=input
xrange=range
reader.close()
x=s.rstrip().split("\n")
return (int(x[0].split()[0],10),[int(e,10) for e in x[1:]])
n,S=init()
v=sorted(S[0:n])
for m in S[n:]:
r=j=0
#k=n-1
k=bisect.bisect_right(v,m-v[0])-1
while j<k and v[j]+v[j+1]<=m:
while v[j]+v[k]>m: k-=1
if r<v[j]+v[k]:
r=v[j]+v[k]
if r==m: break
j+=1
print(r)
Ruby paiza has been updated to eliminate the need to define bsearch. It was slightly faster. After all native code is important.
paizapoh1_read.rb
#!/usr/bin/ruby
#https://github.com/marcandre/backports/blob/master/lib/backports/2.0.0/range/bsearch.rb
unless Range.method_defined? :bsearch
class Range
def bsearch
from = self.begin
to = self.end
to -= 1 if exclude_end?
satisfied = nil
while from <= to do
midpoint = (from + to).div(2)
result = yield(midpoint)
if result
satisfied = midpoint
to = midpoint - 1
else
from = midpoint + 1
end
end
satisfied
end
end
end
S=$<.read.split("\n").map(&:to_i)
n=S[0]
v=S[1,n].sort
S[n+1..-1].each{|m|
r=j=0
k=((0...v.size).bsearch{|i|m-v[0]<v[i]}||v.size)-1 # upper_bound-1
while j<k&&v[j]+v[j+1]<=m
k-=1 while v[j]+v[k]>m
if r<v[j]+v[k]
r=v[j]+v[k]
break if r==m
end
j+=1
end
p r
}
Java I also put a bucket sort
paizapoh1.java
import java.util.*;
class Main{
static final int SIZE=9999999;
static byte[] z=new byte[SIZE];
static int[] _v=new int[1000001],v;
static int count=0;
static int get(){
int r=0;
for(;'0'<=z[count]&&z[count]<='9';)r=r*10+z[count++]-'0';
count++;
return r;
}
public static void main(String[]Z){try{
System.in.read(z,0,SIZE);
int n,d,m,i,j,k,r;
n=get();d=get();
v=new int[n];
for(i=0;i<n;i++)_v[get()]++;
for(i=j=0;j<1000001;j++)for(k=0;k<_v[j];k++)v[i++]=j;
for(i=0;i<d;i++){
m=get();
int idx=Arrays.binarySearch(v,m-v[0]+1);
if(idx<0)idx=~idx;
for(r=j=0,k=idx-1;j<k&&v[j]+v[j+1]<=m;j++){
for(;v[j]+v[k]>m;)k--;
if(r<v[j]+v[k]){
r=v[j]+v[k];
if(r==m)break;
}
}
System.out.println(r);
}
}catch(Exception e){}}
}
C#
paizapoh1.cs
using System;
class PaizaPOH1{
const int SIZE=9999999;
//static string z;
static byte[] z=new byte[SIZE];
static int[] _v=new int[1000001],v;
static int count=0;
static int get(){
int r=0;
for(;'0'<=z[count]&&z[count]<='9';)r=r*10+z[count++]-'0';
count++;
return r;
}
public static void Main(){
//z=Console.In.ReadToEnd();
Console.OpenStandardInput().Read(z,0,SIZE);
int n,d,m,i,j,k,r;
n=get();d=get();
v=new int[n];
for(i=0;i<n;i++)_v[get()]++;
for(i=j=0;j<1000001;j++)for(k=0;k<_v[j];k++)v[i++]=j;
for(i=0;i<d;i++){
m=get();
int idx=Array.BinarySearch(v,m-v[0]+1);
if(idx<0)idx=~idx;
for(r=j=0,k=idx-1;j<k&&v[j]+v[j+1]<=m;j++){
for(;v[j]+v[k]>m;)k--;
if(r<v[j]+v[k]){
r=v[j]+v[k];
if(r==m)break;
}
}
Console.WriteLine(r);
}
}
}
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