About this article

This time I will finally write a program I wrote the flow of the program in Part 1, but I do not necessarily write it in that flow, so thank you. The python ver is 3.8.2.

Determining player and com numbers

Here, we will create a program to determine your own number and com number. I'm thinking of playing by myself, so I'll write instructions with print ().

Com number determination

Then from com. I want to determine the numbers at random, so first import the random module. Then let's shuffle [0,1,2,3,4,5,6,7,8,9] to extract the first three characters. If you write specifically

import random
NUMBERS=[0,1,2,3,4,5,6,7,8,9]
random.shuffle(NUMBERS)
com=NUMBERS[0:3]

#print(com)
#[7,0,2]

It will be. Of course, this time it was [7,0,2], but this number changes every time. Next, I will write a program that determines the number of players.

Player number determination

The number of the player is decided, but I think it's okay if it's random. However, I think that some people have a favorite number, so let's make it possible to input ().

for i in range(10**9):
    print("Please enter your favorite 3-digit number with all numbers different")
    X=input()
    if len(X) != 3:
        print("Please use 3 digits")
    else:
        if int(X[0]) in NUMBERS and int(X[1]) in NUMBERS and int(X[2]) in NUMBERS:
            if X[0] == X[1] or X[0] == X[2] or X[2] == X[3]:
                print("Please enter all three numbers differently")
            else:
                player=[int(X[0]) , int(X[1]) , int(X[2])]
                break
        else:
            print("Please use a 3-digit "number"")

This time, I programmed it to input until it became a "3-digit number". Of course, if you fail 10 ^ 9 times, there is nothing you can do about it, but if you do that, you can't help it (appropriate).

Function to confirm EAT, BITE

Next, we will create a program that will check if the called number is xEAT, yBITE. Let's name the function NUMERON

def NUMERON(CALL,ANS):
    EAT=0
    BITE=0
    for i in range(3):
        if CALL[i]==ANS[i]:
            EAT+=1
        elif CALL[i] in ANS and CALL[i]!=ANS[i]:
            BITE+=1
    return [EAT,BITE]

If you explain the program +1 to EAT if there is a place and a number +1 to BITE if it is included but in a different location Will do it.

Up to here for this time

For the time being, it has gradually become more like Numeron. However, I only made a number input program and EAT and BITE functions.

To summarize this program into one

import random

def NUMERON(CALL,ANS):
    EAT=0
    BITE=0
    for i in range(3):
        if CALL[i]==ANS[i]:
            EAT+=1
        elif CALL[i] in ANS and CALL[i]!=ANS[i]:
            BITE+=1
    return [EAT,BITE]

NUMBERS=[0,1,2,3,4,5,6,7,8,9]
random.shuffle(NUMBERS)
com=NUMBERS[0:3]

for i in range(10**9):
    print("Please enter your favorite 3-digit number with all numbers different")
    X=input()
    if len(X) != 3:
        print("Please use 3 digits")
    else:
        if int(X[0]) in NUMBERS and int(X[1]) in NUMBERS and int(X[2]) in NUMBERS:
            if X[0] == X[1] or X[0] == X[1] or X[0] == X[1]:
                print("Please enter all three numbers differently")
            else:
                player=[int(X[0]) , int(X[1]) , int(X[2])]
                break
        else:
            print("Please use a 3-digit "number"")

is. It will be fun if it gets longer gradually! (Is it just me?) Next time, we will finally make AI!