This problem is soberly difficult ... (Ruby)

Count from 0 to 9 (Ruby edition)

problem

Consider a counter that counts from 0 to 9.

0 → 1 → 2 → 3 → 4 → 5 → 6 → 7 → 8 → 9

As an extension of this counter, we considered a counter that can start with any number.

2 → 3 → 4 → 5 → 6 → 7 → 8 → 9 → 0 → 1 (Example starting from 2, the counter returns to 0 when it reaches 9.)

Receive the number n from the input, start the counter from n,

Implement a program that outputs 10 counter values in order.

Value to be entered

The input is given in the following format

n

・ N is the first value of the counter

Expected output

Output the 10 counter values starting with n in order, separated by line breaks.

Input example 1

0

Output example 1

0 1 2 3 4 5 6 7 8 9

Input example 2

2

Output example 2

2 3 4 5 6 7 8 9 0 1

My answer (I couldn't solve it after all)

python

n = 2
#Reset to 0 when n reaches 10, pass otherwise and output 10
for i in n..9 do
if n == 9
   n = 0
   puts i
   n += 1
end
end

I played with it too much and probably did it for about 2 hours, so in the end it will be the code I gave up lol

Anyway, when I try to go to 10, I need a code that returns to 0 and restarts, but I struggled to write that code at n == 9. This is where the programming brain is lacking. .. .. And after all, verbalization when googled is quite difficult at such times.

that's all!