According to TechAcademy magazine, the sort method was written as follows. "The sort function is a function for sorting the list. You can sort the list of numbers and strings in ascending or descending order. 』
Also, about how to use "The sort function can be used in the form of" list name.sort () ". You can also optionally set the argument reverse. By default, reverse is False, so if you use reverse without setting it, it will be in ascending order. You can do it in descending order by setting reverse = True. 』
Actually, it seems to be a sort method, but aside from the details. According to the above, the sort method is a method that manipulates the ordering of elements in a "list", for example.

>>>str_list = list("qiita") >>>str_list.sort() >>>print(str_list) ['a', 'i', 'i', 'q', 't']

Or

>>>str_list = list("qiita") >>>str_list.sort(reverse=True) >>>print(str_list) ['t', 'q', 'i', 'i', 'a']

It seems that you should say.

What is a sorted function and how to use it

According to the dot blog "The sorted function is one of Python's built-in functions that sorts (sorts) elements in an object that has multiple elements such as lists, tuples, dictionaries, sets, and strings, and returns them in a new list." Is written, for example

>>>x = (5, 8, 4, 1, 3, 2, 7, 6) >>>y = sorted(x, reverse=True) >>>print(y)

Even if you enter

[8, 7, 6, 5, 4, 3, 2, 1]

Seems to be output. To make tuples

>>>x = (5, 8, 4, 1, 3, 2, 7, 6) >>>y = tuple(sorted(x, reverse=True)) >>>print(y)

If so, it seems to be tupled and output. Also, if you use the sorted function in the dictionary

>>>sorted({1: 'D', 2: 'B', 3: 'B', 4: 'E', 5: 'A'}) [1, 2, 3, 4, 5]

It seems that the elements of the dictionary are listed and output.

What's the difference

By the way, most of the answers have been given so far, so I will write them in a comprehensive form. -The sort method can be applied only to the list, and the original list is used as it is for sorting. -On the other hand, the sorted function is effective for iterable ones, and after sorting, put elements in a new list. There was a difference like that. It's a digression from here, For the sort method and sorted function, if you specify key = function as an argument, It seems that sorting is performed based on the value of the function as a comparison standard. For example, according to the Python 3.9 documentation

Example of case-insensitive string comparison:

>>>sorted("This is a test string from Andrew".split(), key=str.lower) ['a', 'Andrew', 'from', 'is', 'string', 'test', 'This']

Other

>>>student_tuples = [ ('john', 'A', 15), ('jane', 'B', 12), ('dave', 'B', 10), ] >>>sorted(student_tuples, key=lambda student: student[2]) # sort by age [('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]

It seems that you can also use it as described above. (capture) If key = function name, it seems that the function of the function is first executed for each element of the iterable object, and then the function is sorted. For example, in the above two examples, In the former, it seems that each element of the character string listed first is replaced with all lowercase letters and then sorted. (However, it returns to the original element at the time of output.) Therefore, it seems that the sorting will be carried out regardless of the size. Then, since the latter uses a lambda expression, that is,

>>>def ~~(student): return student[2]

Therefore, each element of the above list (that is, the above tuple) is assigned to the actual argument of this anonymous function, and the value whose index number is 2 is returned as the return value, and then that is used as the comparison target. Sort. One thing I wondered here. "If the above index numbers are the same, what is the next comparison? 』
Can anyone please teach me?

Huh. I wrote it for the first time, but it takes time and physical strength. Next time, I would like to write if there is something that interests me. If you have any mistakes, please let us know.

Thank you for staying with us on a long and long journey to the end. Also thank you next time.