[Python] Find coordinates from two angles and distance

Overview

In an object that has a parent-child relationship It can be used when the child object moves when the parent object rotates.

Reference code

Execution environment: Motionbuilder 2015

I made a process to draw a sphere with Null in MB. The main processing is only the contents of getPosition ().

• For those who do not know MB FB ○○ is for MB only. Please change to the one that suits the software and language you want to use.

# -*- coding: utf-8 -*-

from pyfbsdk import *
import math

#Method to find coordinates from two angles and distance
def getPosition(_angle1, _angle2, _radius):
    x = _radius * math.sin(math.radians(_angle1)) * math.cos(math.radians(_angle2));
    y = _radius * math.sin(math.radians(_angle1)) * math.sin(math.radians(_angle2));
    z = _radius * math.cos(math.radians(_angle1));
    return FBVector3d(x, y, z);

#If you change this for software for the software you want to use, it will draw a sphere.
## angle1,You can also draw a semicircle by adjusting the value that goes into angle2
##Note that executing step of the third argument of range with 1 (or not specified) is heavy.
parentPos = FBVector3d(50, 50, 50)
for angle1 in range(0, 360, 3):
    for angle2 in range(0, 180, 3):
        mdlNull = FBModelNull("Null_{0}_{1}".format(str(angle1), str(angle2)))
        mdlNull.Show = True
        mdlNull.Scaling = FBVector3d(1, 1, 1)
        mdlNull.Translation = parentPos + getPosition(angle1, angle2, 100.0)

When you run it, you will get something like this. (This made the step of range () in 1!)