Java Integer comparison (==) does not work correctly

phenomenon

import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in); //"2 10000000 10000000" comes in
        int n = sc.nextInt();
        List<Integer> list = new ArrayList<>();
        for (int i = 0; i < n; i++) list.add(sc.nextInt());

        for (int i = 0; i < n-1; i++) {
            if (list.get(i) == list.get(i+1)) {
                System.out.println("equal");
                return;
            }
        }
        System.out.println("Not equal");
    }
}

list.get (i) should be 10000000, and list.get (i + 1) should be the same 10000000, but the result is "not equal". why? ??

Primitive type is ==, object type is ʻequals`

Since Integer is an object type, when comparing with ==, it seems that it will be "not equal" because it will check whether it is the same instance.

import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in); //"2 10000000 10000000" comes in
        int n = sc.nextInt();
        List<Integer> list = new ArrayList<>();
        for (int i = 0; i < n; i++) list.add(sc.nextInt());

        for (int i = 0; i < n-1; i++) {
            if (list.get(i).equals(list.get(i+1))) {
                System.out.println("equal");
                return;
            }
        }
        System.out.println("Not equal");
    }
}

//result
//equal

In conclusion, when comparing numbers, I had to be careful to use == for primitive types and ʻequals` for object types.