[Python] How to change the date format (display format)

How to change the date format (display format) in python

When the date type is output as a character string, the default is "yyyy-mm-dd". Change this to any format, such as "yyyy / mm / dd" or "yyyy year m month d day".

• The list format is "yyyy-mm-dd". Only strings can be reformatted.

table of contents

1. ["Two" ways to change the date](#Two ways to change the date)
2. [[0 padded] date format change (example: yyyy / mm / dd)](# 1 date format change example yyyymmdd)
3. [(1-1) Change with strptime method](# 1-1 Change with strptime method)
4. [Change with (1-2) format method](Change with # 1-2 format method)
5. [[0 padded] date format change (example: yyyy year m month d day)](# 2 date format change example yyyy year m month d day)
6. [(2-1) Change with strptime method](# 2-1 Change with strptime method)
7. [Change with (2-2) format method](Change with # 2-2 format method)
8. [Use (2-3) year, month, day methods](use # 2-3 year-month-day methods)
9. [Use (2-4) replace method](Use # 2-4 replace method)

"Two" ways to change the date

** ① Use strptime method ** ** ② Use format method **

(1-1) Change with strptime method

.strftime('%Y/%m/%d') └ Example: "today.strftime ("% Y /% m /% d ")" └ "% Y": Decimal number in the Christian era (4 digits) (% y is 2 digits) └ "% m": Decimal month filled with 0 (% M is minutes) └ "% d": 0-filled decimal date (% D is mm / dd / yy)

Source code

import datetime as dt
today = dt.date.today()  #Output: datetime.date(2020, 3, 22)

today.strftime("%Y/%m/%d")

#Output result
#'2020/03/22'

Type is a string 「type(today.strftime("%Y/%m/%d"))」：str

Source code

import datetime as dt
today = dt.date.today()  #Output: datetime.date(2020, 3, 22)

'{0:%Y/%m/%d}'.format(today)

#Output result
#'2020/03/22'

Type is a string 「type('{0:%Y/%m/%d}'.format(today))」：str

-Used when there are multiple dates in the argument of format ()

Example of using index number

#Create 3 dates
today = dt.date.today()
past = dt.date(2015,1,1)
future = dt.date(2030,1,1)

#Change index number (0)~2)

'{0:%Y/%m/%d}'.format(today,past,future)
#output:'2020/03/22'

'{1:%Y/%m/%d}'.format(today,past,future)
#output:'2015/01/01'

'{2:%Y/%m/%d}'.format(today,past,future)
#output:'2030/01/01'

(2-1) Change with strptime method

.strftime('%Y/%#m/%#d') └ Example: "today.strftime ("% Y /% # m /% # d ")" └ "% Y": Decimal number in the Christian era (4 digits) (% y is 2 digits) └ "% # m": 0 unfilled decimal month (% M is minutes) └ "% # d": 0 unfilled decimal date (% D is mm / dd / yy)

** ▼ 0 How to make it unfilled **

• Windows: Add "#" (Example: "% # m")
• Mac: Add "-" (Example: "% -m")

Source code(windows)

today = dt.date.today() 
today.strftime("%Y year%#m month%#d day")

#Output result
#'March 22, 2020

Source code

today = dt.date.today() 
'{0:%Y year%#m month%#d day}'.format(today)

#Output result
#'March 22, 2020

Source code

today = dt.date.today() 
str(today.year)+"Year"+str(today.month)+"Month"+str(today.day)+"Day"

#Output result
#'March 22, 2020

Source code

today = dt.date.today() 
y = today.strftime("%Y year")
md = today.strftime("%m month%d day").replace("0","")
y+md

#Output result
#'March 22, 2020

[Back to top](How to change the date format display format with #python)