I want to get the information of the class that inherits the UserDetails class of the user who is logged in with Spring Boot.

environment

Spring Boot 2.4.0 java 1.8 thymeleaf 3.0.11 Spring Security 2.4.0

What you want to achieve

I want to get the information of the class that inherits USERDETAILS of the logged-in user.

I tried various things and managed to realize

It took almost a whole day. I don't think I understand Spring Boot properly, but I've looked at various sites and tried it, and it worked, so I'll keep a record of it.

Classes that inherit from USERDETAILS

Tenants class
Staff class

Login authentication

The loadUserByUsername method of the MyUserDetailsService class separates the returned classes.

MyUserDetailsService class


public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
		//Throw an exception if the argument is null
    if (Objects.isNull(username)) {
      throw new UsernameNotFoundException("username is empty");
	  }
    Tenants tenants = tenantRepository.findByAdminId(username);
    Staff staff = staffRepository.findByEmail(username);
    //Throw an exception if null is returned
    if(tenants != null) {
    	return tenants;
    } else if(staff != null) {
    	return staff;
    } else {
    	throw new UsernameNotFoundException("Not found username: " + username);
    }

	}

controller

I want to display which class is currently logged in with the controller that displays the top screen after login.

As a result of various trials, it is now possible to get which class is authenticated with the implementation below.

@GetMapping("/top")
public ModelAndView userTop(eModelAndView mv, Principal principal) {
	
        //Get a class that inherits USERDETAILS of the logged-in user
	Authentication auth = (Authentication) principal;
	String authClass = auth.getPrincipal().getClass().getSimpleName();
	if(authClass.equals("Tenants")) {
		System.out.println("It's a tenant class! !!");
		String tenantId = ((Tenants)auth.getPrincipal()).getId().toString();
		httpServletResponse.addCookie(new Cookie("tenantId", tenantId));
	}
	if(authClass.equals("Staff")) {
		System.out.println("Staff class! !!");
		String tenantId = ((Staff)auth.getPrincipal()).getTenantId().toString();
		httpServletResponse.addCookie(new Cookie("tenantId", tenantId));
	}
}

Where I was addicted

I don't know how to use Principal or Authentication, ・ How to pass arguments ・ How to use @AuthenticationPrincipal annotation ・ Do you need a cast? ・ I have a Tenants class in the Principal, but I can't retrieve the field? -GetClass () appears in the code assistant, but I get an error and can't execute it? etc. .. ..

Apparently, Principal contains all the records of the class that inherited UserDetails when the authentication was successful.

However, only username can be retrieved. .. ..

I just thought I should use Principal, but apparently it wasn't.

It was an image that the Principal class was included in the Authentication class and the UserDetails class was included in the Principal. (I don't know if it fits)

Just with that image

//First get Authentication from the Principal passed to the controller argument
Authentication auth = (Authentication) principal;
String authClass = auth.getPrincipal() //Get Principal
   .getClass() //Get class
   .getSimpleName(); //Exclude package name

This flow worked.

the first Do I need to cast to Principal → Authentication? ?? I felt like, but it didn't work unless I did this.

How to display in view with thymeleaf

<div sec:authentication="principal"></div>
<div th:text="${#authentication.principal}"></div>

The same content is displayed for both. It's much easier to get it with a controller.

And you can see that the Principal contains User Details.

Summary

//controller
//Pass Principal principal as an argument
public ModelAndView userTop(eModelAndView mv, Principal principal) {
//controller
//Pass Principal principal as an argument
Authentication auth = (Authentication) principal;
//Get Principal from Authentication
String authClass = auth.getPrincipal()
   .getClass()
   .getSimpleName();

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