[PYTHON] Deploy Flask with ZEIT Now
I had a hard time trying to get Python (Flask) to work with NOW. The official document is also hard to see, so I will summarize it again.
Run Flask at a minimum
If you just run Flask, this works. The important point is the builds of now.json.
index.py
from flask import Flask
app = Flask(__name__)
@app.route("/")
def index():
return "hello"
requirements.txt
flask==1.0.2
now.json
{
"version": 2,
"builds": [{ "src": "index.py", "use": "@now/python" }]
}
Supports multiple routes
problem
Suppose you add a routing to index.py that handles / hello.
index.py
from flask import Flask
app = Flask(__name__)
@app.route("/")
def index():
return "hello"
@app.route("/hello")
def world():
return "world"
It looks like it is 404
If you deploy in this state and access / hello, it will be 404.
Avoid by adding routes to now.json
To handle it properly, edit now.json and add routes. Now any request will be processed by wsgi root.
now.json
{
"version": 2,
"builds": [{ "src": "index.py", "use": "@now/python" }],
"routes": [{ "src": "/.*", "dest": "/" }]
}
It seems that the request is being handled normally
Flask is supposed to handle all paths
Since routes have been added, any request that does not exist will be processed via Flask.
Customize 404 pages
You can customize it by looking at Custom Error Page in Flask Official Documentation
index.py
from flask import Flask, jsonify
app = Flask(__name__)
@app.route("/")
def index():
return "hello"
@app.route("/hello")
def world():
return "world"
@app.errorhandler(404)
def resource_not_found(e):
return jsonify(error=str(e)), 404
State
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