Lors de l'utilisation de python2.7.10
Quand j'ai essayé d'utiliser un tel script, Le résultat est que la vitesse de traitement de la carte est plus rapide si elle est simple. (L'utilisation de la mémoire est délicate)
import sys
@profile
def which_is_good():
print sys.version
l = range(100000)
mapped = map(lambda d: chr(65 + d%127), l)
m_stringed = str(mapped[:])
del mapped
del m_stringed
comped = [chr(65 + d%127) for d in l]
c_stringed = str(comped[:])
del comped
del c_stringed
mapped, comped = (), ()
which_is_good()
kernprof -vl run.py
2.7.10 (default, Jul 13 2015, 12:05:58)
[GCC 4.2.1 Compatible Apple LLVM 6.1.0 (clang-602.0.53)]
Wrote profile results to run.py.lprof
Timer unit: 1e-06 s
Total time: 0.155445 s
File: run.py
Function: which_is_good at line 3
Line # Hits Time Per Hit % Time Line Contents
==============================================================
3 @profile
4 def which_is_good():
5 1 33 33.0 0.0 print sys.version
6
7 1 2086 2086.0 1.3 l = range(100000)
8
9 1 49070 49070.0 31.6 mapped = map(lambda d: chr(65 + d%127), l)
10 1 21482 21482.0 13.8 m_stringed = str(mapped[:])
11 1 150 150.0 0.1 del mapped
12 1 23 23.0 0.0 del m_stringed
13
14 100001 68510 0.7 44.1 comped = [chr(65 + d%127) for d in l]
15 1 13911 13911.0 8.9 c_stringed = str(comped[:])
16 1 152 152.0 0.1 del comped
17 1 27 27.0 0.0 del c_stringed
18
19 1 1 1.0 0.0 mapped, comped = (), ()
python -m memory_profiler run.py
2.7.10 (default, Jul 13 2015, 12:05:58)
[GCC 4.2.1 Compatible Apple LLVM 6.1.0 (clang-602.0.53)]
Filename: run.py
Line # Mem usage Increment Line Contents
================================================
3 19.551 MiB 0.000 MiB @profile
4 def which_is_good():
5 19.555 MiB 0.004 MiB print sys.version
6
7 22.660 MiB 3.105 MiB l = range(100000)
8
9 23.426 MiB 0.766 MiB mapped = map(lambda d: chr(65 + d%127), l)
10 28.496 MiB 5.070 MiB m_stringed = str(mapped[:])
11 28.246 MiB -0.250 MiB del mapped
12 27.996 MiB -0.250 MiB del m_stringed
13
14 28.730 MiB 0.734 MiB comped = [chr(65 + d%127) for d in l]
15 28.840 MiB 0.109 MiB c_stringed = str(comped[:])
16 28.590 MiB -0.250 MiB del comped
17 28.340 MiB -0.250 MiB del c_stringed
18
19 28.340 MiB 0.000 MiB mapped, comped = (), ()
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