[Java] Search for substrings / elements (AOJ12 --ring)

I will study using the teaching materials of AIZU ONLINE JUDGE Summarize the operations and grammar you want to perform, An example of actually answering AOJ using that grammar is posted.

Search for substrings with indexOf

• ** indexOf method **
• Search for substrings contained in strings
• On hit, return the index number of the string (first 0)
• ** lastIndexOf method ** searches from the end of the string
• Returns the index of the first found position

public class Main {
    public static void main(String[] args){

		String str1 = "Penpineappleapplepen";
		String str2 = "pineapple";
 
		int result = str1.indexOf(str2);
 
		if (result != -1) {
		    System.out.println(str2 + "Discovery!");
			System.out.println(str2 + "Where was found:" + result);
		} else {
			System.out.println(str2 + "Was not found. .. ..");
		}
	}
}

Discover pineapple!
Where pineapple was found:3

Search for multiple elements with indexOf

• Search multiple elements by specifying the second argument
• Specify the search start position with the second argument of the indexOf method
• When a character hits, specify the next index as the second argument and search for the remaining character strings from the continuation.

import java.util.ArrayList;
import java.util.Arrays;
public class Main {
    public static void main(String[] args){

		String str1 = "Penpineappleapplepen";

        int result;
        for (int i = 0; i < str1.length(); i++) {
            result = str1.indexOf("p", i);
            if (result != -1) {
                i = result;
                System.out.println("p" + result +"Found second!");
            }
        }
	}
}

I found p third!
I found p 8th!
I found p 9th!
I found p 13th!
I found p 14th!
I found p 17th!

Ring (ITP1-8)

Create a program that determines whether a character string p can be created by selecting some characters that are continuous clockwise from an arbitrary position in the ring-shaped character string s as shown in the figure. Input The character string s is given on the first line. The character string p is given on the second line. Output If you can create p, output it to Yes, and if you cannot create it, output it to No. on one line. Constraints

• 1 ≤ p length ≤ s length ≤ 100
• String consists of lowercase letters Sample Input 1 vanceknowledgetoad advance Sample Output 1 Yes

import java.util.Scanner;

public class Main {
    public static void main(String[] args){
        Scanner scan=new Scanner(System.in);
        String s=scan.next();
        String p=scan.next();
        s+=s;
        if(s.indexOf(p)>=0)System.out.println("Yes");
        else System.out.println("No");
        scan.close();
    }
}