[Ruby comprehension check] Can you explain what is happening? && and and

I had an interesting question so I shared it in a test format

phenomenon

def ampersand_return
  puts "foo" && return
  puts "bar"
end

def and_return
  puts "foo" and return
  puts "bar"
end

> ampersand_return
=> nil

> and_return
foo
bar
=> nil

Can you explain what's happening?

Answer

As a general rule, the difference between && and ʻand` lies in its priority.

For && return

&& is calculated first and is equivalent to the following

puts ("foo" && return)

Since " foo " is truthy, return on the right side is processed, and the method returns without outputting anything.

ʻAnd return`

puts" foo " is calculated first and is equivalent to

(puts "foo") and return

Since puts returns nil, the right side of ʻandis not processed, both" foo "and" bar "` are output, and the method ends normally.

At the end

Isn't the documentation specified about operators where method call takes precedence, as in the ʻand example? Yo According to [This Stack Overflow Answer](https://stackoverflow.com/a/42077277/3891638), ʻand, ʻor, ʻif, ʻunless, ʻuntil, while, rescue Seems to behave this way