[PYTHON] paiza coding skill check (seeking leap years)

――Isn't it an unpleasant student if I write this in paiza's coding skill check?

problem

--The problem is in Coding sample on this page. ――The point is to judge the leap year.

My answer

――The conditions for leap year judgment are given as a reference, but the only problem is "Write a program to judge whether the entered integer is a leap year in the Gregorian calendar." ――The condition is divisible by 4, but as a result, February 29th exists in the "leap year", isn't it? ――Why is this answer?

import datetime


def leap(year):
    try:
        datetime.date(int(year), 2, 29)
        return True
    except Exception as inst:
        return False


input_lines = int(input())
for i in range(input_lines):
    year = input()
    is_leap = ("is a leap" if leap(year) else "is not a leap")
    print("{year} {is_leap} year".format(year=year, is_leap=is_leap))

――Of course there is an answer.

$ python leap.py < year.txt
1000 is not a leap year
1992 is a leap year
2000 is a leap year
2001 is not a leap year

is this...

――Maybe it's not straightforward, but what do you think about the hiring side?