loop_count = int(input())


for i in range(loop_count):

    numbers = list(input())#Point 1
    double = [x for x in set(numbers) if numbers.count(x) > 1]#Point 2
   
    if len(dup) == 2:
        print("Two Pair")
    elif len(dup) == 0:
        print("No Pair")
        
    else:
        check = numbers.count(dup[0])#Point 3
        if check == 4:
            print("Four Card")
        elif check == 3:
            print("Three Card")
        elif check == 2:
            print("One Pair")
        else:
            pass

numbers = [1, 1, 4, 5, 1, 4, 4, 6, 4, 9]

double = [x for x in set(numbers) if numbers.count(x) > 1]
#Described in list comprehension

set(numbers) ---> {1, 4, 5, 6, 9} 
#Arrayed by[numbers]It judges what kind of value there is in and returns it with [Set] of a unique list.
#For this reason, for x for x{1, 4, 5, 6, 9}Is entered and processed.

numbers.count(x)
> numbers.count(1)　---> 3
> numbers.count(4)　---> 4
> numbers.count(5)　---> 1 
> numbers.count(6)　---> 1
> numbers.count(9)　---> 1
#Array[numbers]In{1, 4, 5, 6, 9}I'm checking how many of each are included.

numbers.count(x) > 1 
#So, if the number of duplicates is greater than 1, insert the current value into x and add it as an array.
#set{1, 4, 5, 6, 9}Each number is list[number]If there are more than 1(If 2 or more)Add to list. We are doing the processing.

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