[PYTHON] Specify the Django http status code and return.

What you want to solve

-Specify the Http status code in Django and return. -Ajax communication is performed with jQuery, and I want to force fail to be executed under specific conditions.

environment

・ Windows10 premium ・ VScode ・ JQuery

result

Ajax code omitted This is the processing when an appropriate character string is transmitted and the character "test`" is not included in the transmitted character string.

test.py

import HttpResponse

get_post = request.POST["testData"]

if not "test" in get_post:
    response = HttpResponse(status=500) #Specify 500 as the status code
    return response

reference

HTTP Status Code List